---
title: "Predictive Policing - Technical Implementation"
subtitle: "MUSA 5080 - Fall 2025"
author: "Your Name"
date: today
format:
html:
code-fold: show
code-tools: true
toc: true
toc-depth: 3
toc-location: left
theme: cosmo
embed-resources: true
editor: visual
execute:
warning: false
message: false
---
## About This Lab
In this exercise, you will build a spatial predictive model for burglaries using count regression and spatial features.
# Learning Objectives
By the end of this exercise, you will be able to:
1. Create a fishnet grid for aggregating point-level crime data
2. Calculate spatial features including k-nearest neighbors and distance measures
3. Diagnose spatial autocorrelation using Local Moran's I
4. Fit and interpret Poisson and Negative Binomial regression for count data
5. Implement spatial cross-validation (Leave-One-Group-Out)
6. Compare model predictions to a Kernel Density Estimation baseline
7. Evaluate model performance using appropriate metrics
# Setup
```{r setup}
#| message: false
#| warning: false
# Load required packages
library(tidyverse) # Data manipulation
library(sf) # Spatial operations
library(here) # Relative file paths
library(viridis) # Color scales
library(terra) # Raster operations (replaces 'raster')
library(spdep) # Spatial dependence
library(FNN) # Fast nearest neighbors
library(MASS) # Negative binomial regression
library(patchwork) # Plot composition (replaces grid/gridExtra)
library(knitr) # Tables
library(kableExtra) # Table formatting
library(classInt) # Classification intervals
library(here)
# Spatstat split into sub-packages
library(spatstat.geom) # Spatial geometries
library(spatstat.explore) # Spatial exploration/KDE
# Set options
options(scipen = 999) # No scientific notation
set.seed(5080) # Reproducibility
# Create consistent theme for visualizations
theme_crime <- function(base_size = 11) {
theme_minimal(base_size = base_size) +
theme(
plot.title = element_text(face = "bold", size = base_size + 1),
plot.subtitle = element_text(color = "gray30", size = base_size - 1),
legend.position = "right",
panel.grid.minor = element_blank(),
axis.text = element_blank(),
axis.title = element_blank()
)
}
# Set as default
theme_set(theme_crime())
cat("✓ All packages loaded successfully!\n")
cat("✓ Working directory:", getwd(), "\n")
```
# Part 1: Load and Explore Data
## Exercise 1.1: Load Chicago Spatial Data
```{r load-boundaries}
#| message: false
# Load police districts (used for spatial cross-validation)
policeDistricts <-
st_read("https://data.cityofchicago.org/api/geospatial/24zt-jpfn?method=export&format=GeoJSON") %>%
st_transform('ESRI:102271') %>%
dplyr::select(District = dist_num)
# Load police beats (smaller administrative units)
policeBeats <-
st_read("https://data.cityofchicago.org/api/geospatial/n9it-hstw?method=export&format=GeoJSON") %>%
st_transform('ESRI:102271') %>%
dplyr::select(Beat = beat_num)
# Load Chicago boundary
chicagoBoundary <-
st_read("https://raw.githubusercontent.com/urbanSpatial/Public-Policy-Analytics-Landing/master/DATA/Chapter5/chicagoBoundary.geojson") %>%
st_transform('ESRI:102271')
cat("✓ Loaded spatial boundaries\n")
cat(" - Police districts:", nrow(policeDistricts), "\n")
cat(" - Police beats:", nrow(policeBeats), "\n")
```
::: callout-note
## Coordinate Reference System
We're using `ESRI:102271` (Illinois State Plane East, NAD83, US Feet). This is appropriate for Chicago because:
- It minimizes distortion in this region
- Uses feet (common in US planning)
- Allows accurate distance calculations
:::
## Exercise 1.2: Load Burglary Data
```{r load-burglaries}
#| message: false
# Load from provided data file (downloaded from Chicago open data portal)
burglaries <- st_read(here("labs/lab-09/data", "burglaries.shp")) %>%
st_transform('ESRI:102271')
# Check the data
cat("\n✓ Loaded burglary data\n")
cat(" - Number of burglaries:", nrow(burglaries), "\n")
cat(" - CRS:", st_crs(burglaries)$input, "\n")
cat(" - Date range:", min(burglaries$date, na.rm = TRUE), "to",
max(burglaries$date, na.rm = TRUE), "\n")
```
**Question 1.1:** How many burglaries are in the dataset? What time period does this cover? Why does the coordinate reference system matter for our spatial analysis?
*Your answer here:* 7481 points. 2017 with a few points from 2018. The data will be put into a fishnet so the CRS needs to be consistent across all analyses.
::: callout-warning
## Critical Pause #1: Data Provenance
Before proceeding, consider where this data came from:
**Who recorded this data?** Chicago Police Department officers and detectives
**What might be missing?**
- Unreported burglaries (victims didn't call police)
- Incidents police chose not to record
- Downgraded offenses (burglary recorded as trespassing)
- Spatial bias (more patrol = more recorded crime)
**Think About** Was there a Department of Justice investigation of CPD during this period? What did they find about data practices?
:::
## Exercise 1.3: Visualize Point Data
```{r visualize-points}
#| fig-width: 10
#| fig-height: 5
# Simple point map
p1 <- ggplot() +
geom_sf(data = chicagoBoundary, fill = "gray95", color = "gray60") +
geom_sf(data = burglaries, color = "#d62828", size = 0.1, alpha = 0.4) +
labs(
title = "Burglary Locations",
subtitle = paste0("Chicago 2017, n = ", nrow(burglaries))
)
# Density surface using modern syntax
p2 <- ggplot() +
geom_sf(data = chicagoBoundary, fill = "gray95", color = "gray60") +
geom_density_2d_filled(
data = data.frame(st_coordinates(burglaries)),
aes(X, Y),
alpha = 0.7,
bins = 8
) +
scale_fill_viridis_d(
option = "plasma",
direction = -1,
guide = "none" # Modern ggplot2 syntax (not guide = FALSE)
) +
labs(
title = "Density Surface",
subtitle = "Kernel density estimation"
)
# Combine plots using patchwork (modern approach)
p1 + p2 +
plot_annotation(
title = "Spatial Distribution of Burglaries in Chicago",
tag_levels = 'A'
)
```
**Question 1.2:** What spatial patterns do you observe? Are burglaries evenly distributed across Chicago? Where are the highest concentrations? What might explain these patterns?
*Your answer here:* Burglaries are not evenly distributed. The point data might suggest it, but the kernel density shows that there are clusters in the South and North sides of the city. Factors such as population density, vehicle ownership, etc can explain this. I say vehicle ownership because the center of the city (high density) has a low rate of burglaries.
# Part 2: Create Fishnet Grid
## Exercise 2.1: Understanding the Fishnet
A **fishnet grid** converts irregular point data into a regular grid of cells where we can:
- Aggregate counts
- Calculate spatial features
- Apply regression models
Think of it as overlaying graph paper on a map.
```{r create-fishnet}
# Create 500m x 500m grid
fishnet <- st_make_grid(
chicagoBoundary,
cellsize = 500, # 500 meters per cell
square = TRUE
) %>%
st_sf() %>%
mutate(uniqueID = row_number())
# Keep only cells that intersect Chicago
fishnet <- fishnet[chicagoBoundary, ]
# View basic info
cat("✓ Created fishnet grid\n")
cat(" - Number of cells:", nrow(fishnet), "\n")
cat(" - Cell size:", 500, "x", 500, "meters\n")
cat(" - Cell area:", round(st_area(fishnet[1,])), "square meters\n")
```
**Question 2.1:** Why do we use a regular grid instead of existing boundaries like neighborhoods or census tracts? What are the advantages and disadvantages of this approach?
*Your answer here:*
## Exercise 2.2: Aggregate Burglaries to Grid
```{r aggregate-burglaries}
# Spatial join: which cell contains each burglary?
burglaries_fishnet <- st_join(burglaries, fishnet, join = st_within) %>%
st_drop_geometry() %>%
group_by(uniqueID) %>%
summarize(countBurglaries = n())
# Join back to fishnet (cells with 0 burglaries will be NA)
fishnet <- fishnet %>%
left_join(burglaries_fishnet, by = "uniqueID") %>%
mutate(countBurglaries = replace_na(countBurglaries, 0))
# Summary statistics
cat("\nBurglary count distribution:\n")
summary(fishnet$countBurglaries)
cat("\nCells with zero burglaries:",
sum(fishnet$countBurglaries == 0),
"/", nrow(fishnet),
"(", round(100 * sum(fishnet$countBurglaries == 0) / nrow(fishnet), 1), "%)\n")
```
```{r visualize-fishnet}
#| fig-width: 8
#| fig-height: 6
# Visualize aggregated counts
ggplot() +
geom_sf(data = fishnet, aes(fill = countBurglaries), color = NA) +
geom_sf(data = chicagoBoundary, fill = NA, color = "white", linewidth = 1) +
scale_fill_viridis_c(
name = "Burglaries",
option = "plasma",
trans = "sqrt", # Square root for better visualization of skewed data
breaks = c(0, 1, 5, 10, 20, 40)
) +
labs(
title = "Burglary Counts by Grid Cell",
subtitle = "500m x 500m cells, Chicago 2017"
) +
theme_crime()
```
**Question 2.2:** What is the distribution of burglary counts across cells? Why do so many cells have zero burglaries? Is this distribution suitable for count regression? (Hint: look up overdispersion)
*Your answer here:*
# Part 3: Create a Kernel Density Baseline
Before building complex models, let's create a simple baseline using **Kernel Density Estimation (KDE)**.
**The KDE baseline asks:** "What if crime just happens where it happened before?" (simple spatial smoothing, no predictors)
```{r kde-baseline}
#| message: false
# Convert burglaries to ppp (point pattern) format for spatstat
burglaries_ppp <- as.ppp(
st_coordinates(burglaries),
W = as.owin(st_bbox(chicagoBoundary))
)
# Calculate KDE with 1km bandwidth
kde_burglaries <- density.ppp(
burglaries_ppp,
sigma = 1000, # 1km bandwidth
edge = TRUE # Edge correction
)
# Convert to terra raster (modern approach, not raster::raster)
kde_raster <- rast(kde_burglaries)
# Extract KDE values to fishnet cells
fishnet <- fishnet %>%
mutate(
kde_value = terra::extract(
kde_raster,
vect(fishnet),
fun = mean,
na.rm = TRUE
)[, 2] # Extract just the values column
)
cat("✓ Calculated KDE baseline\n")
```
```{r visualize-kde}
#| fig-width: 8
#| fig-height: 6
ggplot() +
geom_sf(data = fishnet, aes(fill = kde_value), color = NA) +
geom_sf(data = chicagoBoundary, fill = NA, color = "white", linewidth = 1) +
scale_fill_viridis_c(
name = "KDE Value",
option = "plasma"
) +
labs(
title = "Kernel Density Estimation Baseline",
subtitle = "Simple spatial smoothing of burglary locations"
) +
theme_crime()
```
**Question 3.1:** How does the KDE map compare to the count map? What does KDE capture well? What does it miss?
*Your answer here:*
::: callout-tip
## Why Start with KDE?
The KDE represents our **null hypothesis**: burglaries happen where they happened before, with no other information.
**Your complex model must outperform this simple baseline to justify its complexity.**
We'll compare back to this at the end!
:::
# Part 4: Create Spatial Predictor Variables
Now we'll create features that might help predict burglaries. We'll use "broken windows theory" logic: signs of disorder predict crime.
## Exercise 4.1: Load 311 Abandoned Vehicle Calls
```{r load-abandoned-cars}
#| message: false
abandoned_cars <- read_csv(here("labs/lab-09/data/abandoned_cars_2017.csv"))%>%
filter(!is.na(Latitude), !is.na(Longitude)) %>%
st_as_sf(coords = c("Longitude", "Latitude"), crs = 4326) %>%
st_transform('ESRI:102271')
cat("✓ Loaded abandoned vehicle calls\n")
cat(" - Number of calls:", nrow(abandoned_cars), "\n")
```
::: callout-note
## Data Loading Note
The data was downloaded from Chicago's Open Data Portal. You can now request an api from the Chicago portal and tap into the data there.
**Consider:** How might the 311 reporting system itself be biased? Who calls 311? What neighborhoods have better 311 awareness?
:::
## Exercise 4.2: Count of Abandoned Cars per Cell
```{r count-abandoned-cars}
# Aggregate abandoned car calls to fishnet
abandoned_fishnet <- st_join(abandoned_cars, fishnet, join = st_within) %>%
st_drop_geometry() %>%
group_by(uniqueID) %>%
summarize(abandoned_cars = n())
# Join to fishnet
fishnet <- fishnet %>%
left_join(abandoned_fishnet, by = "uniqueID") %>%
mutate(abandoned_cars = replace_na(abandoned_cars, 0))
cat("Abandoned car distribution:\n")
summary(fishnet$abandoned_cars)
```
```{r visualize-abandoned-cars}
#| fig-width: 10
#| fig-height: 4
p1 <- ggplot() +
geom_sf(data = fishnet, aes(fill = abandoned_cars), color = NA) +
scale_fill_viridis_c(name = "Count", option = "magma") +
labs(title = "Abandoned Vehicle 311 Calls") +
theme_crime()
p2 <- ggplot() +
geom_sf(data = fishnet, aes(fill = countBurglaries), color = NA) +
scale_fill_viridis_c(name = "Count", option = "plasma") +
labs(title = "Burglaries") +
theme_crime()
p1 + p2 +
plot_annotation(title = "Are abandoned cars and burglaries correlated?")
```
**Question 4.1:** Do you see a visual relationship between abandoned cars and burglaries? What does this suggest?
*Your answer here:*
## Exercise 4.3: Nearest Neighbor Features
Count in a cell is one measure. Distance to the nearest 3 abandoned cars captures local context.
```{r nn-feature}
#| message: false
# Calculate mean distance to 3 nearest abandoned cars
# (Do this OUTSIDE of mutate to avoid sf conflicts)
# Get coordinates
fishnet_coords <- st_coordinates(st_centroid(fishnet))
abandoned_coords <- st_coordinates(abandoned_cars)
# Calculate k nearest neighbors and distances
nn_result <- get.knnx(abandoned_coords, fishnet_coords, k = 3)
# Add to fishnet
fishnet <- fishnet %>%
mutate(
abandoned_cars.nn = rowMeans(nn_result$nn.dist)
)
cat("✓ Calculated nearest neighbor distances\n")
summary(fishnet$abandoned_cars.nn)
```
**Question 4.2:** What does a low value of `abandoned_cars.nn` mean? A high value? Why might this be informative?
*Your answer here:*
## Exercise 4.4: Distance to Hot Spots
Let's identify clusters of abandoned cars using Local Moran's I, then calculate distance to these hot spots.
```{r local-morans-abandoned}
# Function to calculate Local Moran's I
calculate_local_morans <- function(data, variable, k = 5) {
# Create spatial weights
coords <- st_coordinates(st_centroid(data))
neighbors <- knn2nb(knearneigh(coords, k = k))
weights <- nb2listw(neighbors, style = "W", zero.policy = TRUE)
# Calculate Local Moran's I
local_moran <- localmoran(data[[variable]], weights)
# Classify clusters
mean_val <- mean(data[[variable]], na.rm = TRUE)
data %>%
mutate(
local_i = local_moran[, 1],
p_value = local_moran[, 5],
is_significant = p_value < 0.05,
moran_class = case_when(
!is_significant ~ "Not Significant",
local_i > 0 & .data[[variable]] > mean_val ~ "High-High",
local_i > 0 & .data[[variable]] <= mean_val ~ "Low-Low",
local_i < 0 & .data[[variable]] > mean_val ~ "High-Low",
local_i < 0 & .data[[variable]] <= mean_val ~ "Low-High",
TRUE ~ "Not Significant"
)
)
}
# Apply to abandoned cars
fishnet <- calculate_local_morans(fishnet, "abandoned_cars", k = 5)
```
```{r visualize-morans}
#| fig-width: 8
#| fig-height: 6
# Visualize hot spots
ggplot() +
geom_sf(
data = fishnet,
aes(fill = moran_class),
color = NA
) +
scale_fill_manual(
values = c(
"High-High" = "#d7191c",
"High-Low" = "#fdae61",
"Low-High" = "#abd9e9",
"Low-Low" = "#2c7bb6",
"Not Significant" = "gray90"
),
name = "Cluster Type"
) +
labs(
title = "Local Moran's I: Abandoned Car Clusters",
subtitle = "High-High = Hot spots of disorder"
) +
theme_crime()
```
```{r distance-to-hotspots}
# Get centroids of "High-High" cells (hot spots)
hotspots <- fishnet %>%
filter(moran_class == "High-High") %>%
st_centroid()
# Calculate distance from each cell to nearest hot spot
if (nrow(hotspots) > 0) {
fishnet <- fishnet %>%
mutate(
dist_to_hotspot = as.numeric(
st_distance(st_centroid(fishnet), hotspots %>% st_union())
)
)
cat("✓ Calculated distance to abandoned car hot spots\n")
cat(" - Number of hot spot cells:", nrow(hotspots), "\n")
} else {
fishnet <- fishnet %>%
mutate(dist_to_hotspot = 0)
cat("⚠ No significant hot spots found\n")
}
```
**Question 4.3:** Why might distance to a cluster of abandoned cars be more informative than distance to a single abandoned car? What does Local Moran's I tell us?
*Your answer here:*
::: callout-note
**Local Moran's I** identifies:
- **High-High**: Hot spots (high values surrounded by high values)
- **Low-Low**: Cold spots (low values surrounded by low values)
- **High-Low / Low-High**: Spatial outliers
This helps us understand spatial clustering patterns.
:::
------------------------------------------------------------------------
# Part 5: Join Police Districts for Cross-Validation
We'll use police districts for our spatial cross-validation.
```{r join-districts}
# Join district information to fishnet
fishnet <- st_join(
fishnet,
policeDistricts,
join = st_within,
left = TRUE
) %>%
filter(!is.na(District)) # Remove cells outside districts
cat("✓ Joined police districts\n")
cat(" - Districts:", length(unique(fishnet$District)), "\n")
cat(" - Cells:", nrow(fishnet), "\n")
```
# Part 6: Model Fitting
## Exercise 6.1: Poisson Regression
Burglary counts are count data (0, 1, 2, 3...). We'll use **Poisson regression**.
```{r prepare-data}
# Create clean modeling dataset
fishnet_model <- fishnet %>%
st_drop_geometry() %>%
dplyr::select(
uniqueID,
District,
countBurglaries,
abandoned_cars,
abandoned_cars.nn,
dist_to_hotspot
) %>%
na.omit() # Remove any remaining NAs
cat("✓ Prepared modeling data\n")
cat(" - Observations:", nrow(fishnet_model), "\n")
cat(" - Variables:", ncol(fishnet_model), "\n")
```
```{r fit-poisson}
# Fit Poisson regression
model_poisson <- glm(
countBurglaries ~ abandoned_cars + abandoned_cars.nn +
dist_to_hotspot,
data = fishnet_model,
family = "poisson"
)
# Summary
summary(model_poisson)
```
**Question 6.1:** Interpret the coefficients. Which variables are significant? What do the signs (positive/negative) tell you?
*Your answer here:*
## Exercise 6.2: Check for Overdispersion
Poisson regression assumes mean = variance. Real count data often violates this (overdispersion).
```{r check-overdispersion}
# Calculate dispersion parameter
dispersion <- sum(residuals(model_poisson, type = "pearson")^2) /
model_poisson$df.residual
cat("Dispersion parameter:", round(dispersion, 2), "\n")
cat("Rule of thumb: >1.5 suggests overdispersion\n")
if (dispersion > 1.5) {
cat("⚠ Overdispersion detected! Consider Negative Binomial model.\n")
} else {
cat("✓ Dispersion looks okay for Poisson model.\n")
}
```
## Exercise 6.3: Negative Binomial Regression
If overdispersed, use **Negative Binomial regression** (more flexible).
```{r fit-negbin}
# Fit Negative Binomial model
model_nb <- glm.nb(
countBurglaries ~ abandoned_cars + abandoned_cars.nn +
dist_to_hotspot,
data = fishnet_model
)
# Summary
summary(model_nb)
# Compare AIC (lower is better)
cat("\nModel Comparison:\n")
cat("Poisson AIC:", round(AIC(model_poisson), 1), "\n")
cat("Negative Binomial AIC:", round(AIC(model_nb), 1), "\n")
```
**Question 6.2:** Which model fits better (lower AIC)? What does this tell you about the data?
*Your answer here:*
# Part 7: Spatial Cross-Validation
Standard cross-validation randomly splits data. But with spatial data, this means training on cells right next to test cells (information leakage!).
**Leave-One-Group-Out (LOGO) Cross-Validation** trains on all districts except one, then tests on the held-out district.
```{r spatial-cv}
# Get unique districts
districts <- unique(fishnet_model$District)
cv_results <- tibble()
cat("Running LOGO Cross-Validation...\n")
for (i in seq_along(districts)) {
test_district <- districts[i]
# Split data
train_data <- fishnet_model %>% filter(District != test_district)
test_data <- fishnet_model %>% filter(District == test_district)
# Fit model on training data
model_cv <- glm.nb(
countBurglaries ~ abandoned_cars + abandoned_cars.nn +
dist_to_hotspot,
data = train_data
)
# Predict on test data
test_data <- test_data %>%
mutate(
prediction = predict(model_cv, test_data, type = "response")
)
# Calculate metrics
mae <- mean(abs(test_data$countBurglaries - test_data$prediction))
rmse <- sqrt(mean((test_data$countBurglaries - test_data$prediction)^2))
# Store results
cv_results <- bind_rows(
cv_results,
tibble(
fold = i,
test_district = test_district,
n_test = nrow(test_data),
mae = mae,
rmse = rmse
)
)
cat(" Fold", i, "/", length(districts), "- District", test_district,
"- MAE:", round(mae, 2), "\n")
}
# Overall results
cat("\n✓ Cross-Validation Complete\n")
cat("Mean MAE:", round(mean(cv_results$mae), 2), "\n")
cat("Mean RMSE:", round(mean(cv_results$rmse), 2), "\n")
```
```{r cv-results-table}
# Show results
cv_results %>%
arrange(desc(mae)) %>%
kable(
digits = 2,
caption = "LOGO CV Results by District"
) %>%
kable_styling(bootstrap_options = c("striped", "hover"))
```
**Question 7.1:** Why is spatial CV more appropriate than random CV for this problem? Which districts were hardest to predict?
*Your answer here:*
::: callout-note
## Connection to Week 5
Remember learning about train/test splits and cross-validation? This is a spatial version of that concept!
**Why it matters:** If we can only predict well in areas we've already heavily policed, what does that tell us about the model's utility?
:::
# Part 8: Model Predictions and Comparison
## Exercise 8.1: Generate Final Predictions
```{r final-predictions}
# Fit final model on all data
final_model <- glm.nb(
countBurglaries ~ abandoned_cars + abandoned_cars.nn +
dist_to_hotspot,
data = fishnet_model
)
# Add predictions back to fishnet
fishnet <- fishnet %>%
mutate(
prediction_nb = predict(final_model, fishnet_model, type = "response")[match(uniqueID, fishnet_model$uniqueID)]
)
# Also add KDE predictions (normalize to same scale as counts)
kde_sum <- sum(fishnet$kde_value, na.rm = TRUE)
count_sum <- sum(fishnet$countBurglaries, na.rm = TRUE)
fishnet <- fishnet %>%
mutate(
prediction_kde = (kde_value / kde_sum) * count_sum
)
```
## Exercise 8.2: Compare Model vs. KDE Baseline
```{r compare-models}
#| fig-width: 12
#| fig-height: 4
# Create three maps
p1 <- ggplot() +
geom_sf(data = fishnet, aes(fill = countBurglaries), color = NA) +
scale_fill_viridis_c(name = "Count", option = "plasma", limits = c(0, 15)) +
labs(title = "Actual Burglaries") +
theme_crime()
p2 <- ggplot() +
geom_sf(data = fishnet, aes(fill = prediction_nb), color = NA) +
scale_fill_viridis_c(name = "Predicted", option = "plasma", limits = c(0, 15)) +
labs(title = "Model Predictions (Neg. Binomial)") +
theme_crime()
p3 <- ggplot() +
geom_sf(data = fishnet, aes(fill = prediction_kde), color = NA) +
scale_fill_viridis_c(name = "Predicted", option = "plasma", limits = c(0, 15)) +
labs(title = "KDE Baseline Predictions") +
theme_crime()
p1 + p2 + p3 +
plot_annotation(
title = "Actual vs. Predicted Burglaries",
subtitle = "Does our complex model outperform simple KDE?"
)
```
```{r model-comparison-metrics}
# Calculate performance metrics
comparison <- fishnet %>%
st_drop_geometry() %>%
filter(!is.na(prediction_nb), !is.na(prediction_kde)) %>%
summarize(
model_mae = mean(abs(countBurglaries - prediction_nb)),
model_rmse = sqrt(mean((countBurglaries - prediction_nb)^2)),
kde_mae = mean(abs(countBurglaries - prediction_kde)),
kde_rmse = sqrt(mean((countBurglaries - prediction_kde)^2))
)
comparison %>%
pivot_longer(everything(), names_to = "metric", values_to = "value") %>%
separate(metric, into = c("approach", "metric"), sep = "_") %>%
pivot_wider(names_from = metric, values_from = value) %>%
kable(
digits = 2,
caption = "Model Performance Comparison"
) %>%
kable_styling(bootstrap_options = c("striped", "hover"))
```
**Question 8.1:** Does the complex model outperform the simple KDE baseline? By how much? Is the added complexity worth it?
*Your answer here:*
## Exercise 9.3: Where Does the Model Work Well?
```{r prediction-errors}
#| fig-width: 10
#| fig-height: 5
# Calculate errors
fishnet <- fishnet %>%
mutate(
error_nb = countBurglaries - prediction_nb,
error_kde = countBurglaries - prediction_kde,
abs_error_nb = abs(error_nb),
abs_error_kde = abs(error_kde)
)
# Map errors
p1 <- ggplot() +
geom_sf(data = fishnet, aes(fill = error_nb), color = NA) +
scale_fill_gradient2(
name = "Error",
low = "#2166ac", mid = "white", high = "#b2182b",
midpoint = 0,
limits = c(-10, 10)
) +
labs(title = "Model Errors (Actual - Predicted)") +
theme_crime()
p2 <- ggplot() +
geom_sf(data = fishnet, aes(fill = abs_error_nb), color = NA) +
scale_fill_viridis_c(name = "Abs. Error", option = "magma") +
labs(title = "Absolute Model Errors") +
theme_crime()
p1 + p2
```
**Question 9.2:** Where does the model make the biggest errors? Are there spatial patterns in the errors? What might this reveal?
*Your answer here:*
# Part 10: Summary Statistics and Tables
## Exercise 10.1: Model Summary Table
```{r model-summary-table}
# Create nice summary table
model_summary <- broom::tidy(final_model, exponentiate = TRUE) %>%
mutate(
across(where(is.numeric), ~round(., 3))
)
model_summary %>%
kable(
caption = "Final Negative Binomial Model Coefficients (Exponentiated)",
col.names = c("Variable", "Rate Ratio", "Std. Error", "Z", "P-Value")
) %>%
kable_styling(bootstrap_options = c("striped", "hover")) %>%
footnote(
general = "Rate ratios > 1 indicate positive association with burglary counts."
)
```
## Exercise 10.2: Key Findings Summary
Based on your analysis, complete this summary:
**Technical Performance:**
- Cross-validation MAE: `r round(mean(cv_results$mae), 2)`
- Model vs. KDE: \[Which performed better?\]
- Most predictive variable: \[Which had largest effect?\]
**Spatial Patterns:**
- Burglaries are \[evenly distributed / clustered\]
- Hot spots are located in \[describe\]
- Model errors show \[random / systematic\] patterns
**Model Limitations:**
- Overdispersion: \[Yes/No\]
- Spatial autocorrelation in residuals: \[Test this!\]
- Cells with zero counts: \[What % of data?\]
# Conclusion and Next Steps
::: callout-important
## What You've Accomplished
You've successfully built a spatial predictive model for burglaries using:
✓ Fishnet aggregation\
✓ Spatial features (counts, distances, nearest neighbors)\
✓ Spatial autocorrelation diagnostics (Local Moran's I)\
✓ Count regression (Poisson and Negative Binomial)\
✓ Spatial cross-validation (LOGO)\
✓ Comparison to baseline (KDE)
:::
::::::::::
